- #1
harvellt
- 95
- 0
Homework Statement
[tex]\int[/tex]y dx +x dy + z dz
c= helix x = 3 cos t
y = 3 sin t
z = 4t
0[tex]\leq[/tex]t[tex]\leq[/tex]2[tex]\Pi[/tex]
Homework Equations
[tex]\int[/tex] F(x,y,z) ds
ds=[tex]\sqrt{[Fx(x,y,z)]+[Fy(x,y,z)]+[Fz(x,y,z)]}[/tex]dt (still learning latex the partial derivatives are suposed to be squared.)
(also can't figure out how to put in limits of intagration)
The Attempt at a Solution
ds = 5
5[tex]\int[/tex](3 sint + 3 cos t + 4t) =
5[(-3 cos t + 3 sin t + 2t[tex]^{2}[/tex]) evaluated from 0 to 2[tex]\Pi[/tex]
=40[tex]\Pi^{2}[/tex]
My real question is whenever you evaluate sin or cos around all the way around from 0 to 2[tex]\Pi[/tex] is it supposed to be zero? So both the first terms drop out and your left with just 2t[tex]^{2}[/tex]?
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