- #1
chazgurl4life
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The tires of a car make 85 revolutions as the car reduces its speed uniformly from 90 km/h to 30 km/h. The tires have a diameter of 0.80 m.
(a) What was the angular acceleration of the tires?
rad/s2
angular acceleration = Omega final- Omega intial / Delta Time
does that mean that in this case angular acceleration= 30 km/hr-90km/hr /Delta T ...but we don't have Delta T so is there another equation i could use?
(b) If the car continues to decelerate at this rate, how much more time is required for it to stop?
s
(a) What was the angular acceleration of the tires?
rad/s2
angular acceleration = Omega final- Omega intial / Delta Time
does that mean that in this case angular acceleration= 30 km/hr-90km/hr /Delta T ...but we don't have Delta T so is there another equation i could use?
(b) If the car continues to decelerate at this rate, how much more time is required for it to stop?
s