How Do You Calculate Angular Frequency in Simple Harmonic Motion?

In summary, the problem involves a horizontal plank with a mass of 2.0 kg and length of 1.0 m pivoted at one end, with a spring (k = 1000N/m) attached at the other end. The task is to find the angular frequency for small oscillations, which can be calculated using the equation w = (k/m)^0.5. However, the solution involves considering the weight of the plank acting through its center of gravity and the clockwise and anticlockwise moments caused by the reaction in the spring and the weight of the plank, respectively. Taking into account the values of mass and gravity, the spring appears to be stretched by a mass of 1 kg, which can be used
  • #1
myoplex11
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Homework Statement


A horizontal plank (m = 2.0 kg, L = 1.0 m) is pivoted at one end. A spring. (k = 1000N/m) is attached at the other end find the angular frequence for small oscillations?

Homework Equations


w=(k/m)^0.e\5


The Attempt at a Solution



w= (1000/2)^0.5
i have no idea is this a pendulum problem i tried the w=(mgd/I)^0.5 and that also did not work. How do i go about this problem thanks
 
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  • #2
Weight of the plank acts through the CG of the plank.Clock wise moment due to this is 0.5*2*g. If the plank remains horizontal ,anticlockwise moment due to reaction in the spring = F*1 = F = mg = 0.5*2*g. So the spring appears to be stretched by a mass of 1 kg. using this value find w.
 
  • #3


I would approach this problem by first understanding the concept of simple harmonic motion. Simple harmonic motion is a type of periodic motion in which the restoring force is directly proportional to the displacement from equilibrium and acts in the opposite direction of the displacement. In this case, the horizontal plank is acting as a simple pendulum, with the spring providing the restoring force.

To find the angular frequency for small oscillations, we can use the formula w = (k/m)^0.5, where k is the spring constant and m is the mass of the plank. Plugging in the given values, we get:

w = (1000/2)^0.5 = 22.36 rad/s

This means that for small oscillations, the plank will oscillate back and forth with an angular frequency of 22.36 rad/s. This is a measure of how quickly the plank will oscillate and is independent of the amplitude of the oscillations.
 

FAQ: How Do You Calculate Angular Frequency in Simple Harmonic Motion?

What is Simple Harmonic Motion?

Simple Harmonic Motion (SHM) is a type of periodic motion in which an object oscillates back and forth around an equilibrium point with a constant amplitude and period. It is a result of a restoring force that is proportional to the displacement of the object from its equilibrium position.

What are the key characteristics of Simple Harmonic Motion?

The key characteristics of SHM include a constant amplitude, a constant period, and a sinusoidal displacement graph. The motion also follows the principle of superposition, where the total displacement is the sum of two or more individual displacements.

What are some real-life examples of Simple Harmonic Motion?

Some real-life examples of SHM include the motion of a pendulum, a mass on a spring, the vibration of a guitar string, and the motion of a swing. These systems exhibit SHM because they have a restoring force and a stable equilibrium point.

What is the equation for Simple Harmonic Motion?

The equation for SHM is x = A sin(ωt + φ), where x is the displacement from equilibrium, A is the amplitude, ω is the angular frequency, t is time, and φ is the phase angle. This equation can also be written as x = A cos(ωt + φ) or x = A sin(2πft + φ), where f is the frequency in hertz.

How is Simple Harmonic Motion related to energy?

In SHM, the total mechanical energy (potential energy + kinetic energy) of the system is constant. As the object oscillates, the energy is constantly being converted between potential and kinetic. At the equilibrium point, all of the energy is potential, and at the maximum displacement, all of the energy is kinetic. This is known as the law of conservation of energy.

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