How Do You Calculate Average Volume Charge Density in a Layer of Air?

In summary: The difference is 70/m2. The volume has a depth of 100m, so the charge per cubic meter would be 70/m2 x 100m = 7000C/m3.In summary, the average volume charge density in the layer of air between 500m and 600m altitude is 7000C/m3. This can be calculated by applying Gauss' law and considering the difference in electric field between the two elevations.
  • #1
kevinf
90
0
In the air over a particular region at an altitude of 500 m above the ground, the electric field is 150 N/C directed downward. At 600 m above the ground, the electric field is 80 N/C downward. What is the average volume charge density in the layer of air between these two elevations?

the answer is supposed to be in C/m^3. i have looked at this question for a long time now and can not find a way to solve it. i think this problem would be easier if the volume of the slab of air of 100m height can be calculated and then use Gauss' law. but other then that i can not think of any other way to solve it. can anyone help me?
 
Physics news on Phys.org
  • #2
kevinf said:
In the air over a particular region at an altitude of 500 m above the ground, the electric field is 150 N/C directed downward. At 600 m above the ground, the electric field is 80 N/C downward. What is the average volume charge density in the layer of air between these two elevations?

the answer is supposed to be in C/m^3. i have looked at this question for a long time now and can not find a way to solve it. i think this problem would be easier if the volume of the slab of air of 100m height can be calculated and then use Gauss' law. but other then that i can not think of any other way to solve it. can anyone help me?

Well that is what you want to do isn't it?
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/gaulaw.html#c2

Apply Gauss Law. Say you have a 100 x 1 cubic meter closed surface with field lines only going through 2 surfaces - top and bottom.

Isn't the net flux the charge inside, and the charge per cubic meter would be 100th of that?
 
  • #3
so should i just kind of make up a volume since it apparently isn't important?
 
  • #4
kevinf said:
so should i just kind of make up a volume since it apparently isn't important?

It does make a difference.

The only information you are given are for the horizontal surfaces at 500m and 600m. You can ignore the vertical surfaces because the dot product of the E field and the vertical is 0.

You have 150/m2 at the bottom and 80/m2 at the top.
 

FAQ: How Do You Calculate Average Volume Charge Density in a Layer of Air?

What is an electric field?

An electric field is a physical field that surrounds electrically charged particles and exerts a force on other charged particles within its range.

How do you calculate the electric field?

The electric field at a point is calculated by dividing the force on a test charge at that point by the magnitude of the test charge. This can be represented by the equation E = F/q, where E is the electric field in newtons per coulomb (N/C), F is the force in newtons (N), and q is the magnitude of the test charge in coulombs (C).

What is the unit of measurement for electric field?

The SI unit for electric field is newtons per coulomb (N/C). However, it can also be measured in volts per meter (V/m).

What factors affect the strength of an electric field?

The strength of an electric field is affected by the magnitude and distance of the charges creating the field, as well as the medium in which the field exists. It also depends on the direction in which the field is measured.

How is an electric field represented?

An electric field is often represented by field lines, which show the direction and strength of the field at different points. The lines point in the direction of the force that a positive test charge would experience if placed in the field.

Back
Top