- #1
Dx
[SOLVED] Capacitance potential
Hello,
I have 2 questions here to ask for help with?
1) a .2F cap is desired. What area must the pplates have if they are to be separated by a 2.2mm air gap?
My formula i used with substition was C=e_o (A/d) with e_o = 8.85x10^-12.
I rounded my answer it was 4.5 so rounded it to 5x10^7m^2 is this correct?
2)What is the potential at a distance of 5 x 10^-10 m from the nucleus of charge +60e?
I donno if my formula is correct? ids it V=Ed?
I donno how to solve for this, can you help point me that way.
Thanks!
Dx
Hello,
I have 2 questions here to ask for help with?
1) a .2F cap is desired. What area must the pplates have if they are to be separated by a 2.2mm air gap?
My formula i used with substition was C=e_o (A/d) with e_o = 8.85x10^-12.
I rounded my answer it was 4.5 so rounded it to 5x10^7m^2 is this correct?
2)What is the potential at a distance of 5 x 10^-10 m from the nucleus of charge +60e?
I donno if my formula is correct? ids it V=Ed?
I donno how to solve for this, can you help point me that way.
Thanks!
Dx