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puzzledup
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Homework Statement
A square has a charge at each corner. The square is 2cm x 2cm. In the upper left corner there is 1μc, in the upper right corner there is 2μc, the lower right corner there is 3μc, and the lower left corner there is 4μc.
A. What is the magnitude and direction of the electric field at the 4μc charge?
B. wha Tia the magnitude and direction of the force on the 4μc charge?
Homework Equations
E=kq/r^2. And F=EQ
The Attempt at a Solution
1. (9*10^9)(1*10^-6)/(.02)^2 = 2.25*10^7 N/C
2. Same process with 2*10^-6 to get. 4.5*10^7 N/ C
3. Same with 3*10^-6 to get 6.75*10^7 N/C
E net = 2.25+4.5+6.75=13.5*10^7 N/C.
But not sure how to get direction. Since they are all positive, would it be 45° SE?
For force, F=(13.5*10^7)(1.6*10^-19)=21.6*10^-12N.
How to get direction? Pythagorean to be used but how?
Any help is appreciated.