- #1
jaumzaum
- 434
- 33
Consider that I have 2 adiabatic containers, one with a monoatomic gas at pressure P1, volume V1 and temperature T1 and another with pressure P2, volume V2, temperature T2. If I open a valvule and mix the two gases, how do I calculate the equilibrium pressure and temperature?
I know the final quantity of moles, and the final volume, so I need a system of 2 eq to calculate the temperature and pressure. One is the Clapeyron Law, what is the other? I mean, what variable remains constant in this system?
If I try to solve it using conservation of energy:
dU1+dW1+dU2+dW2=0
But how would I calculate the work done by the gases, as this is an irreversible transformation?Thanks!
I know the final quantity of moles, and the final volume, so I need a system of 2 eq to calculate the temperature and pressure. One is the Clapeyron Law, what is the other? I mean, what variable remains constant in this system?
If I try to solve it using conservation of energy:
dU1+dW1+dU2+dW2=0
But how would I calculate the work done by the gases, as this is an irreversible transformation?Thanks!