- #1
luysion
- 35
- 0
hey for this question
If a 2kg sample of aluminium absorbs 64.4 kJ of heat from its surrounds by how much does its temperature increase
the answer is 65.1
how? i got 32.5
q=mcT
T=q/mc=(64.6x10^3)/(2000x.9930)
also same for this question
If 0.5g of an organic compound is completely combusted in air in a constant press calorimeter with a heat capacity of 510 J K-1 a temperature rise of 5.9 degrees is recorded. The heat of combustion (kJ g-) of the compound is approximately
the answer is 3009...
i convered C to c then used q=mcT
which gave me 3009 J , so shouldn't it be 3.00 kJ
so 3.00/0.5 to get kJ per gram
If a 2kg sample of aluminium absorbs 64.4 kJ of heat from its surrounds by how much does its temperature increase
the answer is 65.1
how? i got 32.5
q=mcT
T=q/mc=(64.6x10^3)/(2000x.9930)
also same for this question
If 0.5g of an organic compound is completely combusted in air in a constant press calorimeter with a heat capacity of 510 J K-1 a temperature rise of 5.9 degrees is recorded. The heat of combustion (kJ g-) of the compound is approximately
the answer is 3009...
i convered C to c then used q=mcT
which gave me 3009 J , so shouldn't it be 3.00 kJ
so 3.00/0.5 to get kJ per gram