- #1
Ronaldo95163
- 77
- 1
Homework Statement
Given the following switch positions in time, sketch a graph of the instantaneous power dissipated in the 50 ohm resistor with time.
Homework Equations
P=I^2R=V^2/R=IV
The Attempt at a Solution
Basically I treated the inductor as a short circuit and obtained the current through the circuit as 0.4A so the power dissipated in the 50ohm resistor would be I^2R = 8W
For the Capacitive circuit I used KCL to get a differential eqn:
20-v/50 = v/1x10^-3 + (1x10^-3)dv/dt
Solving that I got v = 400/21e^-21t+400/21
which I then squared and divided by R = 50 to obtain an expression for power which I used to sketch the graph.