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JGrecs
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Homework Statement
each phase of a three phase delta connected generator supplies a full load current of 100A at a voltage of 240V and at a power factor of 0.6 lagging.
Find:
a) line voltage
b) line current
c) the kVA rating
d) the KW
2. The attempt at a solution
a) Line voltage = Phase Voltage (in delta)
VP= VL/1.732
VP= 240/1.732
VP= 138.5V
Therefore the line voltage is 138.5 volts.
b) Phase current at full load= 100A
Line current= Phase current x 1.732
IL= (100)(1.732)
IL= 173.2A
Therefore the line current is 173.2 amps.
c) kVA= (1.732)(VL)(IL)/1000
=(1.732)(240)(173.2)/1000
= 700VA
d) P= (1.732)(VL)(IL)(0.6)
= (1.732)(240)(173.2)(0.6)
= 43kW
How do these answers look? I am a little unsure of which voltages/currents to substitue into the kVA and P formulas.
Thanks,
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