How Do You Calculate Missing Factors in Process Calibration?

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In summary, the conversation is asking for help converting the missing factors in the given items, using linear interpolation. The missing factors are the current process reading for an output signal of 4-20 mA and a current signal reading of 12 mA, a current process reading for an output signal of 4-20 mA and a current signal reading of 14 mA, a current process reading for an output signal of 4-20 mA and a current signal reading of __ mA, and a current process reading for an output signal of 3-15 PSI and a current signal reading of 6 PSI.
  • #1
buddylee
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Can some one please explain how to do this. i want to understand how to do this and the book really doesn't explain it.

Convert the following to find the missing factors in the items below.

Process Range-----Output Signal-----Current Process Reading--Current Signal Reading
Example 0-50 PSIG----- 4-20 mA----- 25 PSI ----------------------12 mA
1 200-800 F------ 4-20 mA ------ _____F --------------- -----14 mA
2 0-1000 GPM------ 4-20 mA ------ 250 GPM----------------------__mA
3 100-300 PSI---- 3-15 PSI ------ _____PSI ------------------ 6 PSI
 
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  • #2
Hint: try linear interpolation.
 
  • #3
Hi buddylee. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

buddylee said:
Convert the following to find the missing factors in the items below.

Process Range-----Output Signal-----Current Process Reading--Current Signal Reading

200-800 F------ 4-20 mA ------ _____F --------------- -----14 mA

Can you explain what you think the question is asking you to do here?
 
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As a scientist, it is important to have a clear understanding of the variables and units involved in a process. In order to find the missing factors in the items provided, you will need to use basic algebraic equations.

In the first example, we are given the process range of 0-50 PSIG and the current process reading of 25 PSI. We also know that the output signal is 4-20 mA and the current signal reading is 12 mA. Based on this information, we can set up the following equation:

(25 PSI - 0 PSIG) / (50 PSIG - 0 PSIG) = (12 mA - 4 mA) / (20 mA - 4 mA)

Solving for the missing factor, we get:

(25 PSI - 0 PSIG) / (50 PSIG - 0 PSIG) = (12 mA - 4 mA) / (20 mA - 4 mA)
25 PSI / 50 PSIG = 8 mA / 16 mA
25 PSI / 50 PSIG = 1/2
25 PSI = (1/2) x 50 PSIG
25 PSI = 25 PSIG

Therefore, the missing factor in this example is 25 PSI.

Using the same approach, we can solve for the missing factors in the other examples:

Example 1:
(_____F - 200 F) / (800 F - 200 F) = (14 mA - 4 mA) / (20 mA - 4 mA)
Solving for the missing factor, we get:
(_____F - 200 F) / (800 F - 200 F) = (14 mA - 4 mA) / (20 mA - 4 mA)
600 F / 600 F = 10 mA / 16 mA
600 F / 600 F = 5/8
600 F = (5/8) x 600 F
600 F = 375 F

Therefore, the missing factor in this example is 375 F.

Example 2:
(250 GPM - 0 GPM) / (1000 GPM - 0 GPM) = (_____mA - 4 mA) / (20 mA - 4 mA)
Solving for the missing factor, we get:
(250 GPM - 0 GPM) / (1000 GPM - 0 GPM) = (
 

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