- #1
Haley Heldt
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Homework Statement
An 82 kg man drops from rest on a diving board 3 m above the surface of the water and comes to rest .55 s after reaching the water. What is the net force on the diver as he is brought to rest
Homework Equations
FDt = mv F = mg v^2 = vi^2 = 2aDx Dx = 3m Dt = .33 s m = 82 kg g = 9.8m/s^2
The Attempt at a Solution
I have plunged the numbers into the equation and i found the velocity to be 7.6 m/s. Also I am pretty sure mg= 803.6 N I am just super confused on how to find the net force please help! thanks!