- #1
pumpernickel
- 8
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Hi. I am a little stuck and I would appreciate some help.
What is the acceleration due to gravity of the sun at the distance of 1.6 X 10^11 m? The asteroid revolves around the sun in 398 Earth days.
2. Homework Equations :
F= (m*V^2)/r3. The Attempt at a Solution :
First I found the circumference: 1.00 * 10 ^12 m
Converted 398 to seconds --> 85968000 sec
So I used that to come up with a velocity --> 1.00 * 10 ^12 m/85968000 sec = 11694 m/s
And did F= (V^2)/r and came up with .000855
I know I am doing this wrong but I just don't know what to do.
Thanks for your help!
What is the acceleration due to gravity of the sun at the distance of 1.6 X 10^11 m? The asteroid revolves around the sun in 398 Earth days.
2. Homework Equations :
F= (m*V^2)/r3. The Attempt at a Solution :
First I found the circumference: 1.00 * 10 ^12 m
Converted 398 to seconds --> 85968000 sec
So I used that to come up with a velocity --> 1.00 * 10 ^12 m/85968000 sec = 11694 m/s
And did F= (V^2)/r and came up with .000855
I know I am doing this wrong but I just don't know what to do.
Thanks for your help!