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Puny
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Homework Statement
The one end of the thermocouple is placed in 45C water, the other end in oil of unknown temperature. Of the voltmeter connected to it's end I got 1.35mV. If the sensitivity of the thermocouple is 0.05mV/C, what will the difference of temperature of the liquids be?
Homework Equations
This is really what I'm looking for. Not sure at all what equation I would use.
The Attempt at a Solution
Would doing something like:
1.35mV / 0.05mV/C = 27C
Would 27C be the difference
Thanks for any input