- #1
toshiba_girl
- 2
- 0
Homework Statement
For this problem the atwood's machine is used. There is a simulation where, m1 is 1.0 kg and m2 is 1.1 kg. Mass m2 rests on the floor that exerts a normal force, FN, on m2. There is no motion (i.e.. the system is in equilibrium). What is the normal force, FN, and what is the tension, T, in the rope? T (at t = 2.54 s) = ______. At equilibrium: FN + T – m2 • g = 0. Then FN = _______. For the simulation, at t=2.54 s, the tension of the pulley system is stated to be 9.789 N. Therefore I was wondering whether this value for tension is the value to be used or whether tension in the rope is to be calculated by other means.
Homework Equations
FN + T - M2 * g = 0
The Attempt at a Solution
I was thinking that maybe FN = (1.1 * 9.8) - (1.0*9.8) = 0.98 N
and T = (1.1 * 9.8) + (1.0 * 9.8) = 20.58 N
However this response does not seem to be correct to me. Can anyone please help me out. Thanks