- #1
phys62
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A transverse wave is traveling on a string. The displacement y of a particle from its equilibrium position is given by y = (0.0230 m) sin (34.6t - 2.04x). Note that the phase angle 34.6t - 2.04x is in radians, t is in seconds, and x is in meters. The linear density of the string is 1.90 x 10-2 kg/m. What is the tension in the string?
I figured since y=0.0230 sin (34.6t-2.04x) the frequency=34.6 wavelength=3.08 and Amplitude=0.0230
Then I think I can solve for velocity using v=wavelength*frequency and get v=106.568
Now I am stuck as to what I am supposed to do.. I think I have to multiply the amplitude by 4 and then use it somewhere.. Perhaps this equation: v=squareroot of F/(m/L)
But now I am lost! Any help would be greatly appreciated! Thank you!
I figured since y=0.0230 sin (34.6t-2.04x) the frequency=34.6 wavelength=3.08 and Amplitude=0.0230
Then I think I can solve for velocity using v=wavelength*frequency and get v=106.568
Now I am stuck as to what I am supposed to do.. I think I have to multiply the amplitude by 4 and then use it somewhere.. Perhaps this equation: v=squareroot of F/(m/L)
But now I am lost! Any help would be greatly appreciated! Thank you!