- #1
Evolution17
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An 11KG weight and 33KG weight are suspended by a rope on a pulley. There is an air-resistance force of 77N working on all objects. Determine the acceleration.
Fg=mg Fnet=ma ma=f1on2+f2on1
The force of gravity on the 11KG weight is 107.8N (11*9.8) and since this weight will be pulled up (lighter) the 77N works with, coming out to be 184.8N. For the second weight, Fg=323.4N and the Ff will work against it since it is moving down (400.4N). Then I have no clue where to take it next, I could subtract the forces and get 216N and then divide it by the mass but that is clearly wrong. Any further help (or demonstration on how to use the 1on2 2on1 formula) would be greatly appreciated.
Fg=mg Fnet=ma ma=f1on2+f2on1
The force of gravity on the 11KG weight is 107.8N (11*9.8) and since this weight will be pulled up (lighter) the 77N works with, coming out to be 184.8N. For the second weight, Fg=323.4N and the Ff will work against it since it is moving down (400.4N). Then I have no clue where to take it next, I could subtract the forces and get 216N and then divide it by the mass but that is clearly wrong. Any further help (or demonstration on how to use the 1on2 2on1 formula) would be greatly appreciated.