- #1
KaseyK
- 8
- 0
This question was actually a 3 part question. I answered (a) and (b) correctly however I can't figure out how to calculate the 'final velocity of the skydiver'. Here are the givens:
x axis
v1 - 90 m/s
acceleration - zero
delta t - 10.6 seconds
delta d - 958.5 m
Y axis
v1 = 0
delta t - 10.6 seconds
acceleration = -9.8 m/s^2
delta d = 550 m
I was already asked to calculate the vertical velocity of the skydiver which was 100 m/s.
However now they want me to find the final velocity. I was thinking about using the equation:
V2= V1 + a (delta t)
When I use this equation though I don't come up with the right answer, which is supposed to be 130 m/s.
Help!
x axis
v1 - 90 m/s
acceleration - zero
delta t - 10.6 seconds
delta d - 958.5 m
Y axis
v1 = 0
delta t - 10.6 seconds
acceleration = -9.8 m/s^2
delta d = 550 m
I was already asked to calculate the vertical velocity of the skydiver which was 100 m/s.
However now they want me to find the final velocity. I was thinking about using the equation:
V2= V1 + a (delta t)
When I use this equation though I don't come up with the right answer, which is supposed to be 130 m/s.
Help!