- #1
enantiomer1
- 13
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A bowling ball weighing 71.2 N is attached to the ceiling by a 3.90 m rope. The ball is pulled to one side and released; it then swings back and forth like a pendulum. As the rope swings through its lowest point, the speed of the bowling ball is measured at 4.30 m/s
I've figured out that acceleration = 4.74 m/s2
Now all I need to know is the force of tension in the rope , I've tried FT= ma
but that isn't working so I'm stuck
anyone know what equation I'm missing?
I've figured out that acceleration = 4.74 m/s2
Now all I need to know is the force of tension in the rope , I've tried FT= ma
but that isn't working so I'm stuck
anyone know what equation I'm missing?