- #1
tua28494
- 10
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This isn't really homework, Its just a problem I'm trying to learn to solve. I'm not taking a chemistry course so I'm learning on my own.
Calculate the pH of a solution that is 0.65 M NH4OH and 0.35 M NH4Cl.
Well we can calulate the pOH = -log(OH-) and 14-pOH = pH
I guess I need the equilibrium concentration of OH-.
here is the chemical formula. I believe is necessary
NH4OH -> NH4SUB]+/SUP] + OH-/SUP]
the Kb/SUB] =1.5 x 10-3SUP]
Calculate the pH of a solution that is 0.65 M NH4OH and 0.35 M NH4Cl.
Well we can calulate the pOH = -log(OH-) and 14-pOH = pH
I guess I need the equilibrium concentration of OH-.
here is the chemical formula. I believe is necessary
NH4OH -> NH4SUB]+/SUP] + OH-/SUP]
the Kb/SUB] =1.5 x 10-3SUP]