How Do You Calculate the Power Emitted by a Sound Source?

In summary, the intensity at a distance of 6.0m from a source that is radiating equally in all directions is 6.0x10^-10 W/m^2, and the power emitted by the source can be calculated using the formula P = I(4πr^2), which results in a power of 2.7x10^-7 W. Multiple choice answers are given, and the correct answer is 2.7x10^-7 W.
  • #1
Eternalmetal
17
0

Homework Statement


The intensity at a distance of 6.0m from a source that is radiating equally in all directions is 6.0x10^-10 W/m^2. What is the power emitted by the source?

They give you multiple choice answers, and the answer is 2.7x10-7 W.



Homework Equations



I is proportional to 1/r^2.

B = 10log(I/10^-12)


The Attempt at a Solution



I don't really know how to approach getting the solution, I have tried working backwards from the solution and kind of got nowhere. I see no reason to use the decibel formula because there is no need to indicate loudness, so the only other formula I have to work with is a proportion. Could somebody please help me with the formulas/logic needed to solve this problem? I have a terrible professor and my book is no help. Thanks.
 
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  • #2
Bump. I still need help with this, I put in a bunch of time and I am still lost. I would really appreciate a formula or concept explanation or anything, I have the answer but I just want to know how to do it.
 
  • #3
I don't know but since u haven't got a reply I am just guessing..

there is some formula i can't remember it is something like...

I =p/4pieR^2


P= I(4)(pie)(r)^2 that gives u like 2.7 x 10 ^-6 W

so it might be wrong and i guess it is since u gave teh answer already but find the power formula and it should be as simple as plugging in..
 

FAQ: How Do You Calculate the Power Emitted by a Sound Source?

What is the definition of sound wave intensity?

Sound wave intensity is a measure of the amount of energy that is transmitted through a sound wave per unit of area. It is typically measured in watts per square meter (W/m²).

What factors affect the intensity of sound waves?

The intensity of a sound wave can be affected by several factors, including the amplitude (or height) of the wave, the distance from the source of the sound, and the medium through which the sound wave travels. The type and shape of the source also play a role in determining the intensity of a sound wave.

How is sound wave intensity different from sound pressure?

Sound intensity and sound pressure are two different ways of measuring the strength of a sound wave. While sound intensity measures the amount of energy in the wave, sound pressure measures the amount of force exerted by the wave on a surface. Sound pressure is measured in pascals (Pa).

Is sound wave intensity the same as loudness?

No, sound wave intensity and loudness are not the same. Loudness is a subjective measure of how loud a sound appears to the human ear, while intensity is an objective measure of the physical properties of the sound wave itself. However, there is a correlation between the two, as a higher sound wave intensity typically results in a louder perceived sound.

How can sound wave intensity be measured?

Sound wave intensity can be measured using specialized equipment such as a sound level meter or an acoustic intensity probe. These devices measure the pressure fluctuations in the sound wave and calculate the intensity based on the area and distance from the source. Sound intensity can also be calculated using mathematical formulas, but this method is not as accurate as direct measurement.

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