- #1
stonecoldgen
- 109
- 0
I'm given that x=cos3θ and that y=sin3θ
if (d2y/dx2)=[(dy/dθ)/(dx/dθ)]/[dx/dθ] is right, wouldn´t the second derivative of the parametric be:
1/3c3θ ??
I got this by using dy/dθ=3sin2θ,
and dx/dθ=-3cos2θsinθ
any idea what's wrong? or is it right?
if (d2y/dx2)=[(dy/dθ)/(dx/dθ)]/[dx/dθ] is right, wouldn´t the second derivative of the parametric be:
1/3c3θ ??
I got this by using dy/dθ=3sin2θ,
and dx/dθ=-3cos2θsinθ
any idea what's wrong? or is it right?