- #1
NasuSama
- 326
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2
A chimney (length L = 82.6 m, mass M = 2280 kg) cracks at the base, and topples. Assume:
- the chimney behaves like a thin rod, and it does not break apart as it falls
- only gravity (no friction) acts on the chimney as if falls
- the bottom of the chimney tilts but does not move left or right
Find vcm, the linear speed of the center of mass of the chimney just as it hits the ground.
τ = Iα
τ = rF
ω_f² = ω_0² + 2aθ
v = ωr
τ = mgL/2
τ = Iα
mgL/2 = 1/12 * mL² * α
α = 6g/L
ω = √(2αθ) [I was thinking that θ = π/2, but this gives incorrect answer]
v = ωr
= √(2αθ)r
But the whole answer is wrong
Homework Statement
A chimney (length L = 82.6 m, mass M = 2280 kg) cracks at the base, and topples. Assume:
- the chimney behaves like a thin rod, and it does not break apart as it falls
- only gravity (no friction) acts on the chimney as if falls
- the bottom of the chimney tilts but does not move left or right
Find vcm, the linear speed of the center of mass of the chimney just as it hits the ground.
Homework Equations
τ = Iα
τ = rF
ω_f² = ω_0² + 2aθ
v = ωr
The Attempt at a Solution
τ = mgL/2
τ = Iα
mgL/2 = 1/12 * mL² * α
α = 6g/L
ω = √(2αθ) [I was thinking that θ = π/2, but this gives incorrect answer]
v = ωr
= √(2αθ)r
But the whole answer is wrong