- #1
jmm5872
- 43
- 0
A wooden bar when struck vibrates as a transverse standing wave with three antinodes and two nodes. The lowest frequency note is 43.6 Hz, produced by a bar 55.4 cm long. Find the speed of transverse waves on the bar.
I assumed that 3 antinodes and 2 nodes means the eigenfrequency f=3/2(v/L). I also assumed that 43.6 Hz was the fundamental frequency. Since I want f3, I multiplied 43.6 by 3 and got 130.8 Hz.
From here I plugged into the first equation 130.8=(3/2)(v/.554) and solved for v.
v=48.3088 m/s.
But this answer was wrong, so I am not sure what I did wrong.
I would appreciate any advice, Thanks,
Jason
I assumed that 3 antinodes and 2 nodes means the eigenfrequency f=3/2(v/L). I also assumed that 43.6 Hz was the fundamental frequency. Since I want f3, I multiplied 43.6 by 3 and got 130.8 Hz.
From here I plugged into the first equation 130.8=(3/2)(v/.554) and solved for v.
v=48.3088 m/s.
But this answer was wrong, so I am not sure what I did wrong.
I would appreciate any advice, Thanks,
Jason