How Do You Calculate the Total Displacement of a Car Accelerating Uniformly?

In summary, the problem asks for the displacement of a car that starts at a speed of 11.3m/s and uniformly speeds up until it reaches 18.5 m/s after 45 seconds. By using the equations v(1)=at+v(o) and v^2=v(o)^2 +2a(x-xo), the displacement is found to be 670.5m. However, the actual answer is 1.52km, as the question is asking for the displacement of the entire trip.
  • #1
intenzxboi
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0

Homework Statement



If a car cruises at 11.3m/s for 75s, then uniformly speeds up until, after 45s, it reaches a speed of 18.5 m/s, what is the car's displacement during this motion?

Homework Equations



v(1)=at+v(o)
v^2=v(o)^2 +2a(x-xo)

The Attempt at a Solution



V(o)=11.3
V(1)=18.5
t=45

a=7.2/45=.16

so by plugging in all this values into v^2=v(o)^2 +2a(x-xo) i get 670.5m

But they are telling me the answer is 1.52km
 
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  • #2
nm solved it.. its asking for the displacement of the whole trip..

man i hate how the questions are worded in a tricky way.
 
  • #3


I would approach this problem by first checking the given values to ensure they are accurate and consistent. The given values for initial and final velocities, as well as the time, seem reasonable. However, there is a discrepancy between the acceleration calculated using the given values and the acceleration given in the problem statement. The calculated acceleration is 0.16 m/s^2, while the given acceleration is 7.2 m/s^2. This could be a typo or a mistake in the calculation.

Assuming that the given acceleration is correct, the displacement can be calculated using the equations provided in the homework statement. Using the equation v(1) = at + v(0), we can solve for the displacement (x-x0) at t=45 seconds, which is the time when the car reaches its final velocity of 18.5 m/s. This gives us a displacement of 405.5 m.

To find the total displacement, we also need to consider the initial motion of the car at a constant velocity of 11.3 m/s for 75 seconds. Using the equation x = v(0)t, we can calculate the displacement during this initial motion, which is 847.5 m.

Therefore, the total displacement of the car during this motion is 405.5 m + 847.5 m = 1253 m, which is equivalent to 1.25 km. This is closer to the given answer of 1.52 km, but there may still be a slight discrepancy due to rounding errors or other factors. It is important to always double-check calculations and given values to ensure accuracy in scientific analysis.
 

FAQ: How Do You Calculate the Total Displacement of a Car Accelerating Uniformly?

What is constant acceleration?

Constant acceleration is the rate at which an object's velocity changes over time remains constant. This means that the object is moving in a straight line, and its velocity is changing by the same amount every second.

How is constant acceleration different from variable acceleration?

Constant acceleration means that the object's velocity is changing at a constant rate, while variable acceleration means that the object's velocity is changing at different rates throughout its motion.

What is the formula for calculating constant acceleration?

The formula for constant acceleration is a = (vf - vi)/t, where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time taken for the change in velocity.

What are some examples of constant acceleration in real life?

An object falling due to gravity, a car moving at a constant speed, and a bullet fired from a gun are all examples of constant acceleration in real life.

How is constant acceleration represented on a velocity-time graph?

On a velocity-time graph, constant acceleration is represented by a straight line with a constant slope. The steeper the slope, the greater the acceleration.

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