- #36
Byrgg
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You said earlier that acceleration isn't considered in either of these situations, I thought it would be, considering the fact that velocity is changing.
Byrgg said:Ok, so let me try to understand this, if you're adding vectors, you're getting the final velocity? For some reason, I'm having a hard time understanding that adding 5 m/s [N] and 5m/sresults in a final velocity of 0, the 5 m/sis the change, right? Does this still apply in two dimensional cases? I'm thinking that the final velocity may not be represented by the resultant vector of adding all of the vectors in a two dimensional case, but I'm probably wrong. Should I be thinking of vetors as a change in velocity, rather than an actual velcoity? ...QUOTE]
The flow of the water say being 5 m/s N and the rower rowing 5 m/s S. His resultant velocity will then be 0 m/s (relative to the embankment). That is he will be standing still, but if we consider another example of an object moving 5 m/s S and a little while later 5 m/s N, then the change in his velocity will be 10 m/s N in order to change from 5 m/s S to 5 m/s N.
Byrgg said:Also, in an earlier example, the equation C = A - B was supposed to represent the change in velocity, if B is the final vector, should the change be represented by C = B - A?