- #1
Pablo1122
- 21
- 0
Alright, so after looking at this video to do it
I did the following.
F1(65N) = 65cos(30)i+65sin30i
Then using the radian circle I saw that 30* has x,y coordinates of sqrt3/2 and 1/2 respectively. So as shown in the video I did
65(root3/2)i+65(1/2)j
= 56.3i + 32.5j
I did this for the left one too (30N).
But for the one at the bottom (20N) I get the degree of it to be 250. (270-20) = 250.
250* is not on the radian circle so how can I write 250* in terms of x,y coordinates?
Thanks in advance.