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FVZZBO
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I know you can use Moseley's law to calculate K Alpha X-ray energy. Can this law be used to calculate the K Beta energy?
$$
\Delta E = (-13.6eV)(Z-1)^2\left(\frac{1}{n_{1}^2}-\frac{1}{n_{2}^2}\right)
$$
I saw on http://minerva.union.edu/labrakes/PIXE_Physics100_Lecture3_F14.pdf that they use it to calculate the K Beta wavelength for copper, but this doesn't make sense to me. How could it still be Z-1? Isn't there more screening/shielding because the electron is coming from the M shell?
$$
\Delta E = (-13.6eV)(Z-1)^2\left(\frac{1}{n_{1}^2}-\frac{1}{n_{2}^2}\right)
$$
I saw on http://minerva.union.edu/labrakes/PIXE_Physics100_Lecture3_F14.pdf that they use it to calculate the K Beta wavelength for copper, but this doesn't make sense to me. How could it still be Z-1? Isn't there more screening/shielding because the electron is coming from the M shell?