- #1
danielle36
- 29
- 0
I came across a derivative question on my exam that involved finding the derivative of
[tex]xe^{x}[/tex]
and I realized I wasn't sure what to do with it... I figured you could either use
[tex] f'(x^{n}) = nx^{n-1} [/tex]
and come out with
[tex] xe^{x} [/tex]
or maybe since x is a variable you need to use the multiplication rule?
f'g + g'f
[tex]= e^{x} + xe^{x}[/tex]
(Or maybe something entirely different - this is still new to me )
[tex]xe^{x}[/tex]
and I realized I wasn't sure what to do with it... I figured you could either use
[tex] f'(x^{n}) = nx^{n-1} [/tex]
and come out with
[tex] xe^{x} [/tex]
or maybe since x is a variable you need to use the multiplication rule?
f'g + g'f
[tex]= e^{x} + xe^{x}[/tex]
(Or maybe something entirely different - this is still new to me )