How Do You Normalize a Wavefunction and Calculate Particle Location Probability?

In summary, we use the given wavefunction to determine the normalization constant A by integrating from -L/4 to L/4 and setting the result equal to 1. This leads to A = \pm \frac{2}{{\sqrt L }} but we choose the positive value for simplicity. Then, using this normalization constant, we integrate from 0 to L/8 to find the probability that the particle will be found between x=0 and x=L/8, which is 40.9% or 0.409.
  • #1
squelch
Gold Member
57
1

Homework Statement


A particle is described by the wavefunction:
[tex]\psi (x) = \{ \begin{array}{*{20}{c}}
{A\cos (\frac{{2\pi x}}{L}){\quad\rm{for }} - \frac{L}{4} \le x \le \frac{L}{4}}\\
{0{\quad\rm{otherwise }}}
\end{array}[/tex]

(a) Determine the normalization constant A
(b) What is the probability that the particle will be found between x=0 and x=L/8 if a measurement is made?

2. Homework Equations

N/A

The Attempt at a Solution



Okay, just verify my logic for me:

(a) We integrate the wave function from -L/4→L/4, where the particle has a 100% chance of appearing, and set this integral equal to 1 (for the probability just mentioned):

[tex]1 = \int\limits_{ - \frac{L}{4}}^{\frac{L}{4}} \psi {(x)^*}\psi (x)dx[/tex]

Integrating this (using Mathematica) and solving for A seems to point at [itex]A = \pm \frac{2}{{\sqrt L }}[/itex].

I'll only assume the positive value is valid since I'm not sure we can have a negative probability.

(b) Assuming that the normalization constant in part (a) is correct, we use our new normalization constant in our wavefunction and perform the same integration, this time over 0→L/8. Performing this operation seems to yield 40.9% (0.409).
 
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  • #2
Yes your logic is correct. You're right that we can't have a negative probability, but since the probability comes from ##\psi ^*\psi##, the normalisation constant only ever appears as ##A^2##, so it doesn't matter whether you pick the positive or negative value. Generally we pick the positive one just because positive numbers are easier to think about.
 

FAQ: How Do You Normalize a Wavefunction and Calculate Particle Location Probability?

What is the purpose of normalizing a wavefunction?

The purpose of normalizing a wavefunction is to ensure that the total probability of finding a particle in any location is equal to one. This allows for accurate predictions of the behavior of a quantum system.

How is a wavefunction normalized?

A wavefunction is normalized by dividing it by the square root of the integral of its absolute value squared over all space. This ensures that the total probability of finding a particle in any location is equal to one.

Why is normalization important in quantum mechanics?

Normalization is important in quantum mechanics because it allows for accurate predictions of the behavior of a quantum system. It ensures that the total probability of finding a particle in any location is equal to one, which is crucial for understanding the probabilistic nature of quantum systems.

What happens if a wavefunction is not normalized?

If a wavefunction is not normalized, it means that the total probability of finding a particle in any location is not equal to one. This can lead to inaccurate predictions and violate the fundamental principles of quantum mechanics.

Are there any exceptions to normalizing a wavefunction?

There are some cases where a wavefunction does not need to be normalized, such as when dealing with infinite or unbounded systems. In these cases, a modified normalization procedure may be used to ensure that the wavefunction is still properly normalized.

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