- #1
Jason-Li
- 119
- 14
- Homework Statement
- Working through some fractions in loop-gain of an oscillator and stuck when comparing my answer to the learning materials...
- Relevant Equations
- algebra & fractions
So my final equation is:
##\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}##
I need to boil this down, the learning materials has the following working, but I can't seem to get it
$$\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}$$
$$\frac {3930n^2+2700+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
But I have the following:
$$\frac {(3930n^2+2700)*10^{-5}+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
Not sure why I have the extra 10^{-5} or how to get rid of it?
Unless the following makes mathematical sense? by making 10^{-5} = 1/ 10^{5}
$$\frac {(3930n^2+2700)*10^{5}+2700*3930n^2} {(2700*3930n^2)*10^5}$$
$$\frac {(3930n^2+2700)+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
But the problem is $$\frac {(3930n^2+2700)*10^{5}+2700*3930n^2} {(2700*3930n^2)*10^5} ≠ \frac {(3930n^2+2700)+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
##\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}##
I need to boil this down, the learning materials has the following working, but I can't seem to get it
$$\frac {1} {2700} + \frac {1} {3930n^2} + 10^{-5}$$
$$\frac {3930n^2+2700+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
But I have the following:
$$\frac {(3930n^2+2700)*10^{-5}+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
Not sure why I have the extra 10^{-5} or how to get rid of it?
Unless the following makes mathematical sense? by making 10^{-5} = 1/ 10^{5}
$$\frac {(3930n^2+2700)*10^{5}+2700*3930n^2} {(2700*3930n^2)*10^5}$$
$$\frac {(3930n^2+2700)+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
But the problem is $$\frac {(3930n^2+2700)*10^{5}+2700*3930n^2} {(2700*3930n^2)*10^5} ≠ \frac {(3930n^2+2700)+2700*3930n^2*10^{-5}} {(2700*3930n^2)}$$
Last edited: