How Do You Simplify the Integral in Wald's Quadrupole Formula?

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In summary, to prove the given equation, we can use mathematical principles and techniques to simplify the integral. This involves expanding and rearranging terms, bringing constants outside the integral, using integration by parts, and making substitutions for variables. After evaluating the integral and simplifying the resulting expression, we can compare it with the given equation for P to prove its validity.
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etotheipi
To prove (4.4.58) from Wald$$P = \frac{1}{45} \sum_{\mu, \nu = 1}^{n} \left(\frac{d^3 Q_{\mu \nu}}{dt^3} \right)^2$$from starting by writing$$P = - \frac{d}{dt} \int_S t_{a0} dS^a = - \frac{d}{dt} \int_S - \frac{1}{8 \pi} G_{a0}^{(2)} [ \gamma_{cd} ] dS^a = \frac{1}{8\pi} \frac{d}{dt} \int_S \left(R_{a0}^{(2)} - \frac{1}{2} \eta_{a0} R^{(2)} \right) dS^a$$we know that

$$\begin{align*}

R_{a0}^{(2)} = \frac{1}{2} \gamma^{cd} \partial_a \partial_0 \gamma_{cd} &- \gamma^{cd} \partial_c \partial_{(a} \gamma_{0)d} + \frac{1}{4}(\partial_a \gamma_{cd}) \partial_0 \gamma^{cd} + (\partial^d {\gamma^c}_0) \partial_{[d} \gamma_{c]a} \\

&+ \frac{1}{2} \partial_d(\gamma^{dc} \partial_c \gamma_{a0}) - \frac{1}{4}(\partial^c \gamma) \partial_c \gamma_{a0} - (\partial_{d} \gamma^{cd} - \frac{1}{2} \partial^c \gamma) \partial_{(a} \gamma_{0)c}

\end{align*}$$from which it also follows we can write the ##- \frac{1}{2} \eta_{a0} R^{(2)}## term as

$$\begin{align*}

- \frac{1}{2} \eta_{a0} R^{(2)} =
-\frac{1}{4} \eta_{a0} \gamma^{cd} \partial_e \partial^e \gamma_{cd} & + \frac{1}{2} \eta_{a0} \gamma^{cd} \partial_c \partial_{e} {\gamma^{e}}_{d} - \frac{1}{8} \eta_{a0} (\partial_e \gamma_{cd}) \partial^e \gamma^{cd} - \frac{1}{2} \eta_{a0} (\partial^d {\gamma^c}^e) \partial_{[d} \gamma_{c]e} \\

&- \frac{1}{4} \eta_{a0} \partial_d(\gamma^{dc} \partial_c \gamma) + \frac{1}{8} \eta_{a0} (\partial^c \gamma) (\partial_c \gamma) + \frac{1}{2} \eta_{a0} (\partial_{d} \gamma^{cd} - \frac{1}{2} \partial^c \gamma) \partial_{e} {\gamma^{e}}_{c}

\end{align*}
$$where$$\bar{\gamma}_{\mu \nu} = \frac{2}{3R} \frac{d^2 q_{\mu \nu}}{dt^2} = \gamma_{\mu \nu} - \frac{1}{2} \eta_{\mu \nu} \gamma$$How on Earth are you supposed to do that integral?!? Apparently some terms disappear but which ones?
 
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you can approach this problem by using mathematical principles and techniques to simplify the integral. Here are some steps you can follow:

1. Simplify the expressions for ##R_{a0}^{(2)}## and ##- \frac{1}{2} \eta_{a0} R^{(2)}## using the given equations and the definition of ##\bar{\gamma}_{\mu \nu}##. This will involve expanding and rearranging terms.

2. Use the fact that ##\eta_{a0}## is a constant to bring it outside the integral. This will allow you to simplify the integrand.

3. Use integration by parts to convert the derivatives in the integrand into simpler expressions. This will also involve using the boundary conditions (i.e. assuming that the surface integral is evaluated at some fixed time).

4. Use the fact that ##\gamma_{\mu \nu}## is symmetric to simplify the integrand further.

5. Use the given equation for ##P## to substitute for ##R_{a0}^{(2)}## and ##- \frac{1}{2} \eta_{a0} R^{(2)}## in the integral. This will give you an expression for ##P## in terms of ##\gamma_{\mu \nu}## and its derivatives.

6. Use the given equation for ##P## again to substitute for ##\gamma_{\mu \nu}## in the expression you obtained in step 5. This will give you an expression for ##P## in terms of ##q_{\mu \nu}## and its derivatives.

7. Evaluate the integral by using the boundary conditions and simplifying the resulting expression. Some terms may cancel out, leaving you with a simpler expression for ##P##.

8. Compare the expression you obtained for ##P## with the given equation for ##P## and see if they are equal. If they are, you have successfully proven the equation.

Keep in mind that this is just one possible approach and there may be other ways to simplify the integral. It may also be helpful to consult with a mathematician or a colleague who is familiar with this type of integral. Good luck!
 

FAQ: How Do You Simplify the Integral in Wald's Quadrupole Formula?

What is a quadrupole?

A quadrupole is a type of electromagnetic field that is created by two pairs of electric charges with opposite signs. It is commonly used in physics experiments to manipulate and study particles.

How does a quadrupole work?

A quadrupole works by using two pairs of electric charges, known as poles, to create an electromagnetic field. The charges are arranged in a specific way so that the field is strongest at the center and weaker towards the edges, creating a quadrupole field.

What is the significance of quadrupoles in physics?

Quadrupoles are significant in physics because they are used in many experiments to manipulate and study particles. They are also used in various technologies, such as particle accelerators and mass spectrometers.

What is the difference between a quadrupole and a dipole?

A quadrupole has two pairs of poles, while a dipole only has one pair. This means that a quadrupole has a more complex electromagnetic field compared to a dipole, which has a simpler field.

How are quadrupoles used in mass spectrometry?

In mass spectrometry, quadrupoles are used to separate and analyze particles based on their mass-to-charge ratio. The particles are ionized and then passed through a quadrupole field, where they are separated based on their response to the field.

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