- #1
dan280291
- 8
- 0
Hi I'm really not sure how to start this question. I could do it if it was in terms of z but I'm not sure if trying to change the variable using z = x + iy is correct. If anyone could suggest a method I'd appreciate it.
∫(x3 - iy2)dz
along the path z= [itex]\gamma(t)[/itex] = t + it3, 0≤t≤1
Thanks
∫(x3 - iy2)dz
along the path z= [itex]\gamma(t)[/itex] = t + it3, 0≤t≤1
Thanks