How Do You Solve a Proton's Orbit and Electric Field Problems?

In summary, The conversation is about two physics problems involving electric fields and charge. The first problem involves calculating the linear charge density of a wire based on the properties of a proton orbiting around it. The second problem involves understanding the behavior of the electric field of a ring of charge when the distance from the center is much smaller or much larger than the radius of the ring. The solution to the first problem is -2.29nC/m and the solution to the second problem is determined through the use of Gauss' Law. The person asking for help has already solved both problems.
  • #1
ELHEK
8
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Hey ppl! anyone who can help me with this i will be so grateful! I've been stuck on it for 2 days(dumbarse ) thx!

1) A proton orbits a long chared wire, making 1.0x10^6 revolutions per second. The radius of the orbit is 1.0cm. What is the wire's linear charge density?

2) Show that the on axis electic field of a ring of charge has the expected behaviour when z<<R and when z>>R.

The answer to the first questions is -2.29nC/m, but I am clueless about how to go about it, I've also tried applying circular kinematics but have not been successful. The second question i am absolutly dumbfounded by. Thx again anyone who helps!
 
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  • #2
1) How can you relate the linear charge density and the electric field generated by the wire? (hint: Gauss)

2) Do you know how to (at least in principle) determine the electric field on the axis? (hint: there's no shortcut here)
 
  • #3
tis alright I've solved em both thanks anyway
 

FAQ: How Do You Solve a Proton's Orbit and Electric Field Problems?

What is the "Electric field proton wire problem"?

The "Electric field proton wire problem" is a physics problem that involves calculating the electric field created by a series of protons arranged in a straight line, also known as a proton wire. This problem is commonly used in introductory physics courses to help students understand the concept of electric fields and their effects on charged particles.

How do you calculate the electric field of a proton wire?

To calculate the electric field of a proton wire, you can use the equation E = kq/r^2, where E is the electric field, k is the Coulomb's constant (9x10^9 Nm^2/C^2), q is the charge of a single proton (1.6x10^-19 C), and r is the distance from the proton wire. The electric field from each proton can be calculated separately and then added together to find the total electric field at a given point.

What factors affect the strength of the electric field in a proton wire?

The strength of the electric field in a proton wire is affected by the number of protons in the wire, the distance from the wire, and the charge of the protons. As the number of protons increases, the electric field also increases. However, as the distance from the wire increases, the electric field decreases. The charge of the protons also plays a role, as protons with a higher charge will create a stronger electric field.

How does the electric field of a proton wire change if the wire is curved instead of straight?

If the proton wire is curved instead of straight, the electric field will also change. This is because the distance from the wire will vary at different points along the curve, resulting in a non-uniform electric field. In this case, the electric field must be calculated at each point along the curve and then added together to find the total electric field.

Can the electric field of a proton wire be shielded or cancelled out?

Yes, the electric field of a proton wire can be shielded or cancelled out by using another charged object. This is known as electric field cancellation and is based on the principle that the electric fields from two opposite charges cancel each other out. By placing a negatively charged object near the proton wire, the two electric fields will cancel each other out, resulting in a net electric field of zero.

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