How Do You Solve a Quadratic Equation to Find Dimensions of a Rectangle?

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In summary, the conversation discusses the force exerted by air on a surface, given by the formula F = 10^5A. The task is to find the dimensions of a rectangular surface where the air supplies 10^6 Newtons of force and the length is 2 meters longer than the width. The solution involves using the quadratic formula to solve for the width of the rectangular surface.
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i-love-physics
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Homework Statement



The force (in Newtons) that air exerts on a surface is given by the formula
F = 10^5A

Where A is the surface area (in square metres). Suppose that the air supplies 10^6 Newtons of force on a rectangular surface that is 2 metres longer than it is wide. Find the dimensions (to 2 decimal place) of the rectangular surface.

Homework Equations





The Attempt at a Solution



This is my attempt

10^6 = 10^5A
A= 10

10 = LW
10 = (2+w)w
10= 2w +w^2

now i am stuck here..

If anyone knows what to do it would be greatly appreciated if you could help me out, thank you.
 
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  • #2
Its a quadratic. Could use the quadratic formula
 
  • #3
so what i did was corrent, i just got to use the quadradic formula and that's it yeh?
 
  • #4
As far as I am aware, yes.

For a quadratic like that, the first thing i would do is write it as:

w2+2w-10=0

And see if i can write it in the form (x+a)(x+b)=0. If not, then id probably proceed to use the quadratic formula.
 
  • #5
Starting from w2+ 2w= 10, completing the square leaps to mind!
 

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