How Do You Solve a Skew Lines Distance Problem in Vector Geometry?

In summary, the conversation discusses two skew lines, L1 and L2, with given equations. The goal is to find two points, Q and R, on L1 and L2 respectively, such that the distance between them is equal to 2. The person asking the question is unsure of how to approach the problem and is seeking clarification. Another person suggests finding the closest distance between the two lines, which they have attempted to do and found to be less than 2. They ask if there are any specific points of interest on the lines.
  • #1
thepassenger48
13
0

Homework Statement


Given
Line1: (x,y,x)=(2,1,-1) + t(-1,0,2)
Line2: (x,y,x)=(1,1,3) + s(5,-6,-7)

The lines L1 and L2 are skew; determine points Q and R on lines L1 and L2 respectively such that ||QR|| = 2

2. The attempt at a solution
I have no idea how to even approach this question! Can someone give me a clue? Please

Thank you
 
Last edited:
Physics news on Phys.org
  • #2
Do you know how to find the closest distance between the two lines? I attempted to do it and get sqrt(16/21) which is less than 2. This means, if you imagine the geometry, that there are immensely many points on the two lines that are distance 2 apart. Are there any two in particular that you are interested in?
 
  • #3
for your question. This is a tough vector geometry problem, and it will require some careful thinking and calculations to solve. Here are some steps you can follow to approach this problem:

1. Understand what skew lines are: Skew lines are two lines that do not intersect and are not parallel. This means that they are not on the same plane and do not have the same direction.

2. Understand the equations of the lines: The equations of the lines are given in parametric form, which means that they can be written as a point plus a scalar multiple of a direction vector. For example, line L1 can be written as (2,1,-1) + t(-1,0,2). This means that for any value of t, you can find a point on this line by plugging in t and solving for the coordinates.

3. Use the distance formula: The problem asks for points Q and R on lines L1 and L2, respectively, such that the distance between them is 2. This means that you can use the distance formula to set up an equation to solve for the values of t and s.

4. Set up the equation: Using the distance formula, you can set up an equation with the coordinates of points Q and R, and the direction vectors of lines L1 and L2. You can then solve for t and s using algebraic methods.

5. Find the points: Once you have solved for t and s, you can plug these values back into the equations of lines L1 and L2 to find the coordinates of points Q and R.

I hope this helps you get started on solving this problem. Remember to carefully consider the definitions and equations involved, and don't be afraid to ask for help if you get stuck. Good luck!
 

FAQ: How Do You Solve a Skew Lines Distance Problem in Vector Geometry?

What is vector geometry?

Vector geometry is a branch of mathematics that deals with the geometric properties of vectors. Vectors are mathematical objects that have both magnitude (size) and direction, and can be represented by arrows in a coordinate system.

What makes a vector "tough" in geometry?

A vector can be considered tough in geometry if it involves complex calculations or requires advanced mathematical concepts to solve. This could include finding the angle between two vectors, determining the intersection point of multiple vectors, or finding the components of a vector in a non-standard coordinate system.

How do I solve a tough vector geometry question?

The best approach to solving tough vector geometry questions is to break down the problem into smaller, more manageable parts. Use geometric principles and mathematical formulas to simplify the calculations. It can also be helpful to draw a diagram or visualize the problem to better understand the given information.

Are there any specific rules or formulas for vector geometry?

Yes, there are several rules and formulas that are commonly used in vector geometry. These include the dot product, cross product, and vector projections, among others. It is important to have a solid understanding of these concepts in order to solve tough vector geometry questions.

How is vector geometry used in real life?

Vector geometry has many practical applications in fields such as physics, engineering, and computer graphics. It is used to model and analyze the motion of objects, design structures and machines, and create realistic 3D graphics. It also has uses in navigation, robotics, and many other areas of science and technology.

Similar threads

Back
Top