How Do You Solve for c in a Normal Distribution Problem?

  • Thread starter littlerich
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In summary, the problem involves finding the value of c in the equation P(|X-2|>c)=0.6, where X is a normally distributed random variable with mean 3 and variance 16. The approach taken by the person asking for help involves using the definitions of probability and manipulating them to find the value of c. However, they are currently stuck after reaching the point of obtaining the value 0.2533 from their tables.
  • #1
littlerich
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Normal Distribution: Mean = 3, Variance = 16

P(|X-2|>c)=0.6

Find c.

I'm so stuck...

Please Help Me

Rich
 
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  • #2
First off, you should post homework in the homework forums.

Secondly, we're not here to do your homework for you. (See https://www.physicsforums.com/showthread.php?t=94383) You have to show us what you've tried on the problem, even if you think it is going nowhere! (e.g. it is almost always a good idea to try applying the definitions of things -- some of us get the feeling you haven't even bothered trying to do the problem if you haven't even done that!)

Finally, your post is a little confusing. I suppose you meant to say that X is a normally distributed random variable with mean 3 and variance 16?
 
  • #3
Hey

Yea, that's what i meant...

What I've tried so far is:

P(X>c+2)+P(X<2-c)=0.6

Hence: P(X<c+2)-P(X<2-c)=0.4

And because my tables are backwards i changed it to:

P(X>2-c)-P(X>c+2)=0.4

0.4 then comes up as 0.2533 in the tables, and now I am stuck.
 

FAQ: How Do You Solve for c in a Normal Distribution Problem?

What does "P(|X-2|>c)=0.6" mean?

This notation represents the probability that the absolute value of the difference between a random variable X and 2 is greater than some value c, and that probability is equal to 0.6.

How do I solve for c?

To solve for c, you can use a table of standard normal probabilities or a statistical calculator to find the critical value that corresponds to a probability of 0.6. You can also use algebraic manipulation to isolate c in the equation.

What is the significance of c in this equation?

The value of c in this equation represents the cutoff point for the absolute difference between X and 2. If the absolute difference is greater than c, then the probability is 0.6. This value is often used in statistical hypothesis testing and confidence intervals.

How does this equation relate to the normal distribution?

This equation is related to the normal distribution because it involves the absolute value of the difference between a random variable and a given value. The normal distribution is a commonly used probability distribution that describes the likelihood of a continuous variable falling within a certain range of values.

Can this equation be used for any type of data?

Yes, this equation can be used for any type of data as long as it follows a normal distribution. However, if the data does not follow a normal distribution, alternative methods may need to be used to calculate probabilities and solve for c.

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