How Do You Solve Group Ring Isomorphisms in Mathematics?

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In summary, the given problem asks to prove the isomorphism of certain algebras over a field F. By using the definitions and the Chinese Remainder Theorem, we can show that F[C_2] is isomorphic to F \times F, \mathbb{R}[C_3] is isomorphic to \mathbb{R} \times \mathbb{C}, \mathbb{R}[C_4] is isomorphic to \mathbb{R} \times \mathbb{R} \times \mathbb{C}, and \mathbb{R}[C_6] is isomorphic to \mathbb{R} \times \mathbb{R} \times \math
  • #1
catcherintherye
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I have about 5 questions all of a similar form ...

[tex] \mathbb{F}[C_2] \cong \mathbb{F} \times \mahbb{F} [/tex]

if 1+1 [tex] \neq 0 in \mathbb{F} [/tex]

[tex]\Re [C_3] \cong \Re \times C [/tex]

[tex] \Re [C_4] \cong \Re \times \Re \times C [/tex]

these were on the first sheet given out and I still don't know how to do them after 4 weeks, any help on how to do them??
 
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  • #2
"Do them"? Do you mean prove them? Start by writing out the definitions.
(I would have thought that [itex]\mathbb{F}[/itex] was a field but apparently not.)

What are C2, C3, C4?
 
  • #3
I guess C_n is the cyclic group of order n. But still, what the OP posted doesn't make a lot of sense, e.g. what's the distinction between F and [itex]\mathbb{F}[/itex]? Also, is [itex]\Re[/itex] actually [itex]\mathbb{R}[/itex]? (The former is the "real part" of a complex number, the latter is the set of real numbers.) And, in the last two, what is C? Finally, in what context are the direct products being taken?
 
  • #4
obviously i haven't made myself clear, i'll post the question in it's entirety...

Let A,B be algebras over a field F. We say that A and B are isomorphic over F written [tex] A\cong_F B [/tex] when there exists a bijective ring homomorphism [tex] \varphi : A \rightarrow B [/tex] which is also linear over F, i.e. satisfies [tex] \\\varphi(a\lambda) = \varphi(a) \lambda \mbox{ for all a} \in A \ \lambda \in F [/tex]

show that i) [tex] F[C_2] \cong_F F \times F [/tex] if 1+1 not equal 0 in F
ii) [tex] R[C_3] \cong_R R \times C [/tex]

iii) [tex] \\ R[C_4] \cong_R R \times R \times C [/tex]

iv) [tex]\\ R[C_6] \cong R \times R \times C \times C [/tex]


here R = field of real numbers, C = field of complex numbers, F is an arbitrary field although in the question it is constrained by the given condition. Also all C_n's are cyclics and by F[C_n] we mean the group ring of C_n over F, that is the ring whose elements are linear combinations of the group elements with coefficients in F.
 
  • #5
For some reason this problem popped into my head today, so I gave it another go and managed to solve it. There are two things we need:
(1) [itex]F[C_n] \cong_F F[x]/(x^n - 1)[/itex]. This can be easily proved using the evaluation homomorphism at a generator of C_n.
(2) The http://planetmath.org/encyclopedia/ChineseRemainderTheorem2.html . (The CRT is something that slipped my mind at the time.)

So now we have:
[tex]F[C_2] \cong F[x]/(x^2 - 1) \cong F[x]/(x+1) \times F[x]/(x-1) \cong F \times F[/tex]

[tex]\mathbb{R}[C_3] \cong \mathbb{R}[x]/(x^3 - 1) \cong \mathbb{R}[x]/(x-1) \times \mathbb{R}[x]/(x^2 + x + 1) \cong \mathbb{R} \times \mathbb{C}[/tex]

[tex]\mathbb{R}[C_4] \cong \mathbb{R}[x]/(x^4 - 1) \cong \mathbb{R}[x]/(x-1) \times \mathbb{R}[x]/(x+1) \times \mathbb{R}[x]/(x^2 + 1) \cong \mathbb{R} \times \mathbb{R} \times \mathbb{C}[/tex]

[tex]\mathbb{R}[C_6] \cong \mathbb{R}[x]/(x^6 - 1) \cong \mathbb{R}[x]/(x-1) \times \mathbb{R}[x]/(x+1) \times \mathbb{R}[x]/(x^2+x+1) \times \mathbb{R}[x]/(x^2-x+1) \cong \mathbb{R} \times \mathbb{R} \times \mathbb{C} \times \mathbb{C}[/tex]

Better late than never I suppose!
 
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