How Do You Solve log_{2}8x^{2} When log_{2}x Equals p?

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To solve log_{2}8x^{2} given that log_{2}x = p, first apply the logarithmic property for products: log_{2}(8x^{2}) = log_{2}8 + log_{2}x^{2}. This simplifies to log_{2}8 + 2log_{2}x. Since log_{2}x equals p, substitute to get log_{2}8 + 2p. The final expression is 3 + 2p, confirming the solution is straightforward once the properties of logarithms are applied correctly.
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Homework Statement


Given that log_{2}x = p
a) Find log_{2}8x^{2} in terms of p


The Attempt at a Solution



take the power outside the log

2log_{2}8x

but i can't see what to do next

Any suggestions

Thanks :)
 
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I assume you mean:
{log}_{2}(8x^{2})

First things first. How do logs work with products? log(ab) = ?? (In your example, a = 8 and b = x^2.)
 
log_{2}8x^{2}

log_{2}8 + 2log_{2}x

3 + 2p

Thanks :)

it was easy!
 
Now you've got it! :wink:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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