How Do You Solve Polynomial Equations Using the Factor and Remainder Theorem?

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In summary: Find the remainder when f(x) is divided by (x – 2).This can be done by using the equation for x-2 given in the question and substituting in for x. In summary, the two questions that I am having trouble with are 18) and 19). Both of these questions involve dividing a polynomial by a constant. I was not able to find a solution for either question on my own, but
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DizzyDoo
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A couple of hard questions about the Factor and Remainder Thoerem that I'm having a hard time with.

Homework Statement



18) f(x) = 2x3 + x2 – 5x + c, where c is a constant.
Given that f(1) = 0,

(a) find the value of c

(b) factorise f(x) completely,

(c) find the remainder when f(x) is divided by (2x – 3).

19) f(x) = x3 – 2x2 + ax + b, where a and b are constants.

When f(x) is divided by (x – 2), the remainder is 1.

When f(x) is divided by (x + 1), the remainder is 28.

(a) Find the value of a and the value of b.

(b) Show that (x – 3) is a factor of f(x).


Homework Equations



None

The Attempt at a Solution



These are the last two questions of the homework, and the only ones I am having some difficulty with. The other 17 questions I have finished and am happy with. I reckon I can do 18) a) though;

f(1) = 2(1)^3 + 1² - 5(1) + c
= 2 + 1 -5 + c
c = 2

Right? Any help with the other questions is very welcome! Thanks for your time.
 
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  • #2
Yes c=2 making [itex]f(x)=2x^3 + x^2-5x+2[/itex]

The remainder and factor theorem states that if f(x) is any polynomial and f(x) is divided by x-a then the remainder is f(a).If f(a)=0 then (x-a) is a factor of f(x).

From the theorem above.

f(1)=0. This means that (x-1) is a factor of f(x). Now you can just do long division or synthetic division and you will get the other quadratic factor. which you can then factorize further if possible.
 
  • #3
Hey thanks, that's a great explanation, I've finished off question 18 quite comfortably. Any help with question 19?
 
  • #4
DizzyDoo said:
19) f(x) = x3 – 2x2 + ax + b, where a and b are constants.

When f(x) is divided by (x – 2), the remainder is 1.

When f(x) is divided by (x + 1), the remainder is 28.
They are leading you to a point where you will have two equations in two unknowns.

By the remainder theorem, the first part says that f(x) = (x-2)q(x) + f(2), where q(x) is a quadratic polynomial. This tells you something about f(2). The second part says something similar. Can you put the rest together?
DizzyDoo said:
(a) Find the value of a and the value of b.
This should be accomplished using the two facts above in combination with the remainder theorem.
DizzyDoo said:
(b) Show that (x – 3) is a factor of f(x).
Once you know a and b you should be able to prove this - remember what it means about f(3).
 
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FAQ: How Do You Solve Polynomial Equations Using the Factor and Remainder Theorem?

What is the Factor and Remainder Theorem?

The Factor and Remainder Theorem is a mathematical concept used to find factors and remainders of polynomial equations.

Why is the Factor and Remainder Theorem important?

The Factor and Remainder Theorem is important because it allows us to simplify and solve complex polynomial equations, making them easier to work with and understand.

What is the difference between factors and remainders?

Factors are numbers or expressions that divide evenly into a given polynomial equation, while remainders are the leftover values after dividing the polynomial by its factors.

How do you use the Factor and Remainder Theorem to find factors and remainders?

To use the Factor and Remainder Theorem, you must first factor the given polynomial equation. Then, you can plug in a potential factor as the input and use long division to see if it evenly divides the polynomial. The remainder will be the leftover value.

Can the Factor and Remainder Theorem be applied to all types of polynomial equations?

Yes, the Factor and Remainder Theorem can be applied to all types of polynomial equations, including binomials, trinomials, and higher polynomials with multiple terms and variables.

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