How Do You Solve Simultaneous Equations Using Quadratic Methods?

Now go back and check by substituting x=1 into the original equations. Then check for x=-1/3.In summary, in order to solve simultaneous equations, you can use substitution or elimination. For the quadratic equation, you must make the right hand side equal to 0 before using the quadratic formula. Once you have a solution for one variable, you must go back and check by substituting it into the other original equation to find the solution for the other variable.
  • #1
maali5
35
0

Homework Statement



How do yo solve simultaneos equations?

Homework Equations



Am I right ?


The Attempt at a Solution



y = x2 – 5x + 5 question a



5x + 3y = 30. question b



Find location of points collide?


Add a+b

x2 + 2y -25=0


quadratic formula use

x= -2+ square root(2^2-(4x1x(-25))/2 x = 4.09901

or

x= -2 - square root(2^2-(4x1x(-25))/2 x=-6.09


subsitue y etc
 
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  • #2
maali5 said:

Homework Statement



How do yo solve simultaneos equations?

Homework Equations



Am I right ?


The Attempt at a Solution



y = x2 – 5x + 5 question a



5x + 3y = 30. question b



Find location of points collide?


Add a+b

x2 + 2y -25=0


quadratic formula use

x= -2+ square root(2^2-(4x1x(-25))/2 x = 4.09901

or

x= -2 - square root(2^2-(4x1x(-25))/2 x=-6.09


subsitue y etc

Looks like you are on the right track...
 
  • #3
berkeman said:
Looks like you are on the right track...

Cheerio
 
  • #4
maali5 said:
Add a+b

x2 + 2y -25=0
I would use substitution. You already have equation a solved for y. Plug it into equation b:
5x + 3y = 30
5x + 3(x2 – 5x + 5) = 30
... and so on.
 
  • #5
berkeman said:
Looks like you are on the right track...

Errrm, if eumyang is on the right track, then I'll eat my hat!

... and I'll post the video of it on youtube.
 
  • #6
maali5 said:
...

x2 + 2y -25=0

quadratic formula use

x= -2+ square root(2^2-(4x1x(-25))/2, x = 4.09901

or

x= -2 - square root(2^2-(4x1x(-25))/2, x=-6.09

substitute y etc.
You can't use the quadratic formula on x2 + 2y -25=0, because it has two different variables in it.

B.T.W: Yesterday, Mark44 pointed out to you that you should not use the lower case letter, x, to indicate multiplication.
 
  • #7
Hey ladies ;) + gentleman :)

Now you have "REALLY" lost me.

I went with eumyang- subsituations and this is what I have done.

NB: Allright I WILL USE . FOR MULTIPLY NOW

Ok, let's start

1)

y = x^2 – 5x + 5 question a
5x + 3y = 30. question bFind location of points collide?
Answer;5x + 3(x^2 – 5x + 5) = 30

5x+ 15x^2 -15x+15=30

15x^2-10x+15=30

15x^2-10x -15 = 30

5(3x^2 -2x -3) = 30

use formula

x= 2 + sqrt{40} / 6

x= 1.3874

or

x=2 - sqrt{40} / 6

x= -0.72075Is this the right directions?
 
  • #8
maali5 said:
...

Answer;
5x + 3(x^2 – 5x + 5) = 30

5x+ 15x^2 -15x+15=30
The coefficient of the x2 term is 3, not 15.
15x^2-10x+15=30

15x^2-10x -15 = 30

5(3x^2 -2x -3) = 30

use formula

x= 2 + sqrt{40} / 6

x= 1.3874

or

x=2 - sqrt{40} / 6

x= -0.72075

Is this the right directions?
Once you get a solution for x, you should go back to an original equation to find y. To check your answer for the pair x & y, you should then plug those values into the other original equation.
 
  • #9
NascentOxygen said:
Errrm, if eumyang is on the right track, then I'll eat my hat!

... and I'll post the video of it on youtube.

CORRECTION: I intended to write
Errrm, if maali5 is on the right track, then I'll eat my hat!

... and I'll post the video of it on youtube.
 
  • #10
You must make the right hand side = 0 before using the quadratic formula.

Taking as an example: 15x^2 - 10x - 15 = 30

Make RHS=0:

15x^2 - 10x - 15 - 30 = 30 - 30

x = (10 ± sqrt(100 + 4•15•45)) / 30
 

Related to How Do You Solve Simultaneous Equations Using Quadratic Methods?

1. What are simultaneous equations?

Simultaneous equations are a set of two or more equations that are solved together to find the values of the variables that satisfy all of the equations.

2. How do you solve simultaneous equations?

To solve simultaneous equations, you can use methods such as substitution, elimination, or graphing. These methods involve manipulating the equations to isolate one variable and then substituting its value into the other equations to find the remaining variables.

3. What is the difference between linear and non-linear simultaneous equations?

Linear simultaneous equations have variables raised to the first power only, while non-linear simultaneous equations have variables raised to a power higher than one. Linear simultaneous equations can be solved using the methods mentioned above, while non-linear equations often require more advanced techniques.

4. Can simultaneous equations have more than two variables?

Yes, simultaneous equations can have any number of variables. However, the number of equations must also match the number of variables in order to solve the system.

5. What are some real-life applications of simultaneous equations?

Simultaneous equations are used in a variety of fields such as engineering, economics, and physics to model and solve real-world problems. They can be used to calculate the optimal solution for a business, predict the trajectory of a projectile, or design a circuit for an electrical system.

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