- #1
raider902
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Can someone please help with this question. I know you take two equations and make them equal and then my professor told me you use the quadratic formula to get the answer but I am still no quite getting it.
Hockey player A is standing still when player B passes him with the puck at a rate of 12m/s. Player A watches player B for 3 second then decides to catch up with him. If player A accelerate at 4 m/s^2 what will be the final distance when the two players are even? How long will it take player A to catch up with player B. I think the answer is 8.2 seconds and the distance is 132 meters.
Can someone please give the answers by walking through the problem using the two proper euqation then the quadratic formula.
Hockey player A is standing still when player B passes him with the puck at a rate of 12m/s. Player A watches player B for 3 second then decides to catch up with him. If player A accelerate at 4 m/s^2 what will be the final distance when the two players are even? How long will it take player A to catch up with player B. I think the answer is 8.2 seconds and the distance is 132 meters.
Can someone please give the answers by walking through the problem using the two proper euqation then the quadratic formula.