How Do You Solve the Inverse Function Problem Involving sin^(-1)(cos(7π/5))?

[Karma]

sin-(cos(7pi/5) (arcsin)

i have the equation (x+n2pi) but don't know where to go from their

 

[EnumaElish]

How did you get x+n2pi?

 

[Karma]

f(x + P) = f(x)
the periodic function of cosine is 2pi? no?

 

[HallsofIvy]

sin-(cos(7pi/5) (arcsin)

i have the equation (x+n2pi) but don't know where to go from their

What you've written makes no sense at all! What do you mean by
"sin-(cos(7pi/5) (arcsin)"?? And what does that have to do with an inverse function?