How Do You Solve These Constant Acceleration Problems?

[Meghal]

Hey i do not know how to do ANY of these problems i tried using equations and plugged it in and i don't know how to do it please help...

Homework Statement

1. A golf ball is hit with a velocity of 30 m/s at a 28 Degree angle. what is the max height the ball reaches?


2. A Ball is thrown off a cliff horizontally off a cliff at a velocity of 43 m/s if the ball lands 145m from the base of the cliff how long does it take the ball to reach the ground.


3. A foot ball is projected on a flat surface at a 32 degree angle. If the ball lands 45m from where it started, what is the balls initial velocity

4. A Ball is thrown upward off a cliff at angle of 40degrees horizontally and with a velocity of 35m/s. If it takes 12.5s for the ball to reach the bottom of the cliff, how high is the cliff.

5 A Ball is projected off the top of a 180m high cliff with a velocity of 24 m/s and an angle of 34Degrees. How far from the bottom of the cliff is the ball after 4.2s.

Homework Equations

Equations:

Range = Dx = (initial Velocity)^2 (Sin 2 (theta)) / lgl

d = (initial velocity)(t) + 1/2 (g)(t)^2

d= 1/2 (Initial Velocity + Final Velocity)(t)

Final Velocity = Initial Velocity + g(t)

(Final Velocity)^2 = (Initial velocity)^2 + 2(g)(d)

The Attempt at a Solution

I attempted all the problems but got weird decimal numbers and it didnt LOOK right too much to type for 5 questions... however can someone just tell me which equation to use for each and then if i used it, i will understand if its correct or not... thanks.

 

[rl.bhat]

1)Take the vertical component of the velocity of the ball. When it reaches the maximum height its final velocity is zero. Use fifth equation from your list to find the maximum height.
2)When a Ball is thrown off a cliff horizontally, its velocity remains constant in that direction. So the distance /velocity will give you the answer.
3)You can use the first formula for this problem.
4. Take vertical component of the velocity, and use second formula with proper sign to initial velocity and g.
5)From the above clues, try to solve this problem.

 

[thomate1]

I understand that constant acceleration problems can be difficult to solve, especially if you are not familiar with the equations and how to use them. My suggestion would be to review the equations provided and make sure you understand them before attempting to solve the problems. Additionally, it may be helpful to draw diagrams or make use of online resources or textbooks to better understand the concepts.

To answer your specific questions, here are the equations you can use for each problem:

1. To find the maximum height, you can use the equation d = (initial velocity)^2 (Sin 2 (theta)) / g. In this case, the initial velocity is 30 m/s and the angle is 28 degrees.

2. To find the time it takes for the ball to reach the ground, you can use the equation d = (initial velocity)(t) + 1/2 (g)(t)^2. In this case, the initial velocity is 43 m/s and the distance traveled is 145m.

3. To find the initial velocity, you can use the equation Range = Dx = (initial Velocity)^2 (Sin 2 (theta)) / g. In this case, the range is 45m and the angle is 32 degrees.

4. To find the height of the cliff, you can use the equation d= 1/2 (Initial Velocity + Final Velocity)(t). In this case, the initial velocity is 35 m/s and the angle is 40 degrees. You will also need to use the equation Final Velocity = Initial Velocity + g(t) to solve for the final velocity.

5. To find the distance from the bottom of the cliff, you can use the equation d= 1/2 (Initial Velocity + Final Velocity)(t). In this case, the initial velocity is 24 m/s and the angle is 34 degrees. You will also need to use the equation Final Velocity = Initial Velocity + g(t) to solve for the final velocity.

I hope this helps. Remember, it is important to understand the concepts and equations before attempting to solve the problems. Good luck!