- #1
mkay123321
- 16
- 0
The question is x^2dy/dx + y^2=0 , y(1)=3
I re-arrange the equation to get -1/y^2dy=1/x^2dx
Seperated them, then I integrate both sides to get 1/y=-1/x + c
Now I don't get how they got the answer y=3x/(4x-3), as when I try use the condition I get a different answer, could anyone help? I might have done something wrong in the integration?
I re-arrange the equation to get -1/y^2dy=1/x^2dx
Seperated them, then I integrate both sides to get 1/y=-1/x + c
Now I don't get how they got the answer y=3x/(4x-3), as when I try use the condition I get a different answer, could anyone help? I might have done something wrong in the integration?