- #1
songoku
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- 332
Homework Statement
[tex]\lim_{x \to 0} \frac{tan (cos 4x - 1)}{3x ~ sin (\frac{4}{3} x)}[/tex]
Homework Equations
limit for trigonometry
The Attempt at a Solution
can I do it like this:
[tex]\frac{tan (cos 4x - 1)}{3x ~ sin (\frac{4}{3} x)}[/tex]
[tex]= \frac{- tan (2 sin^{2} 2x)}{3x ~ sin (\frac{4}{3} x)}[/tex]
and then using the property of trigonometry limit, it becomes:
[tex]= \frac{-2 . 4}{3 . \frac{4}{3}}[/tex]
[tex]=-2[/tex]