- #1
fern518
- 6
- 0
Hey everyone.
I've got through most of a problem that involves finding an inverse laplace transform, but I am stuck at one part that requires algebraic manipulation. The function is
1/[s(2s2+2s+1)]
So far I have modified it too look like .5/[s(s+.5)2 +.52](1/.5)
I'm not sure how to modify the function with that extra s in the denominator.
I had seen that the function could be transformed into (1/s) - [(s+.5)+.5]/[(s+.5)2+.52 and then from that the inverse Laplace could be easily obtained, but I am not sure how this transformation was done. I am sure there is a property I'm not thinking of, but any help on this would be greatly appreciated!
I've got through most of a problem that involves finding an inverse laplace transform, but I am stuck at one part that requires algebraic manipulation. The function is
1/[s(2s2+2s+1)]
So far I have modified it too look like .5/[s(s+.5)2 +.52](1/.5)
I'm not sure how to modify the function with that extra s in the denominator.
I had seen that the function could be transformed into (1/s) - [(s+.5)+.5]/[(s+.5)2+.52 and then from that the inverse Laplace could be easily obtained, but I am not sure how this transformation was done. I am sure there is a property I'm not thinking of, but any help on this would be greatly appreciated!