- #1
TeaWay
- 9
- 0
a 400kg cannon fires a cannon ball that exits at a speed of 20 m/s.
A) what was the momentum of the cannon and ball before it was fired ?
B) what is the momentum of the cannon ball alone after it was fired ?
C) what is the speed of the cannon as it recoils ?
Given
m = 400kg
vƒ (ƒ = final) = 20 m/s
vo= 0 m/s
(o = initial, that's the symbol i use for initial :P )
since the cannon ball was sitting in the cannon. so the initial velocity is 0 since
its sitting at rest.
Unknown
p (before)
p (after)
speed
Equations
v = p total / m
Δpƒ = m₁v₂ - m₁v₁ ( is this equation right ? )
also if it recoils meaning the momentum after would be the same as before ?
due to -p = p ?
so it would be like this..
Δp = 400kg(20m/s) - 400kg(0 m/s)
Δp = 8000 kg•m/s
then...
v= 8000 kg•m/s
400kg
v = 20 m/s
i want to make sure i did it right && i think i didn't answer all the questions correctly ; - ;..
A) what was the momentum of the cannon and ball before it was fired ?
B) what is the momentum of the cannon ball alone after it was fired ?
C) what is the speed of the cannon as it recoils ?
Given
m = 400kg
vƒ (ƒ = final) = 20 m/s
vo= 0 m/s
(o = initial, that's the symbol i use for initial :P )
since the cannon ball was sitting in the cannon. so the initial velocity is 0 since
its sitting at rest.
Unknown
p (before)
p (after)
speed
Equations
v = p total / m
Δpƒ = m₁v₂ - m₁v₁ ( is this equation right ? )
also if it recoils meaning the momentum after would be the same as before ?
due to -p = p ?
so it would be like this..
Δp = 400kg(20m/s) - 400kg(0 m/s)
Δp = 8000 kg•m/s
then...
v= 8000 kg•m/s
400kg
v = 20 m/s
i want to make sure i did it right && i think i didn't answer all the questions correctly ; - ;..
Last edited:
… what is the mass of the ball? 
! but thanks for the warm welcome lol.but thank you for trying to help out (: !