- #1
fara0815
- 45
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Hello there!
I am not sure how to get started with this one:
Two half shell rods are welded in a v-shape together and attached to a vertikal axis which rotates with 2 rounds per minute. The angle between the rods is 80 degress. In the rods, there a two balls on each side which are in a certain height (counting from the low end of the v) resting in a equilibrium. How great is the height?
So my guess is, that the centrifugal force has to be the same than the gravity force:
[tex] F_g=F_z = m*g = m*\omega^2*r \\ \omega=2*f\pi*f =12.57 \frac{rad}{sec} [/tex]
So the radius would be :
[tex] r= \frac{g}{\omega^2} \\ \mbox{the height is then} h=\frac{r}{\tan40} = 0.074 m [/tex]
However, it is supposed to be 0,088 m.
Honestly, I am totally clueless about this one and I would be happy if someone could lead me to the solution!
Thank you very much in advance!
I am not sure how to get started with this one:
Two half shell rods are welded in a v-shape together and attached to a vertikal axis which rotates with 2 rounds per minute. The angle between the rods is 80 degress. In the rods, there a two balls on each side which are in a certain height (counting from the low end of the v) resting in a equilibrium. How great is the height?
So my guess is, that the centrifugal force has to be the same than the gravity force:
[tex] F_g=F_z = m*g = m*\omega^2*r \\ \omega=2*f\pi*f =12.57 \frac{rad}{sec} [/tex]
So the radius would be :
[tex] r= \frac{g}{\omega^2} \\ \mbox{the height is then} h=\frac{r}{\tan40} = 0.074 m [/tex]
However, it is supposed to be 0,088 m.
Honestly, I am totally clueless about this one and I would be happy if someone could lead me to the solution!
Thank you very much in advance!
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