I How Does a Qubit Exist as Both 1 and 0 Simultaneously?

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TL;DR Summary
QBITS binary state
I think 10 more IQ points would help me understand quantum physics at the level I'd like. That said, I'd like to know more about Qbits. I've watched several videos about them, and they say that they can be 1 and 0 at the same time. Is that just an analogy to the polarization of the old magnetic core, and on/off state of modern solid state bits, or is the actual physical state of a Qbit actually 1 and 0 at the same time due to superpositioning and then finally becomes binary when detected?
 
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Qbit state is a quantum superposition of two definite states.
 
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Googling something like 'how can a qbit hold multiple values' yields a wealth of simple explanations. Take your pick and ask specific questions.
 

Thread 'Quantum Entanglement is a Kinematic Fact, not a Dynamical Effect'

Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
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Thread 'Is It Known For Sure Infinites In QFT Are Caused Using a Continuum?'

I am reading WHAT IS A QUANTUM FIELD THEORY?" A First Introduction for Mathematicians. The author states (2.4 Finite versus Continuous Models) that the use of continuity causes the infinities in QFT: 'Mathematicians are trained to think of physical space as R3. But our continuous model of physical space as R3 is of course an idealization, both at the scale of the very large and at the scale of the very small. This idealization has proved to be very powerful, but in the case of Quantum...
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Thread 'Lesser Green's function'

Thread 'Lesser Green's function'

The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...
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